Yes this is a valid form of the power equation I+P/E However using the equation to calculate the power and re-using that power to calculate the current from a different applied voltage might be flawed.A device that draws 2 Amps at 13.2 Volts is a 26.4 Watt device. Watts divided by Volts = Amps so the higher the Voltage the lower the Amperage drawn. A 26.4 Watt device at 14.5 Volts is going to draw 1.82069 Amps
I have taken a number of lamp bulbs used on the Fiat Spider systems and applied an increasing DC voltage from a variable power supply to the bulbs. For each bulb the current drawn and bulbs brightness increased as the voltage applied was increased. I started at 0 volts and stopped at 16 volts.
When looking at a light bulb chart most wattages are stated for a specific operating voltage. I'm thinking if the voltage is increased from that stated voltage the wattage would also increase.
I have found the same is true when testing the coolant fan motors, wiper motors and heater fan motors. As the voltage is increased the current increases and the speed of the motor increases.